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Section 11.7 Electric Field Due to a Uniformly Charged Ring

You should practice calculating the electric field \(\vec{E}(\vec{r})\) due to some simple distributions of charge, especially those with a high degree of symmetry.

Activity 11.7.1. The electric field due to a uniformly charged ring.

Find the electric field everywhere in space due to a uniformly charged ring with total charge \(Q\) and radius \(R\text{.}\) Then determine the series expansions that represent the electric field due to the charged ring, both on axis and in the plane of the ring, and both near to and far from the ring.

Hint.

In the activity in Section 11.7, you will have found an integral expression for the electric field due to a uniform ring of charge, then used power series methods to approximate the integral in various regions. This activity has much in common with the electrostatic ring activity in Section 9.6, which you may want to review at this time. In addition to the ideas discussed in the hints to that activity you may have needed to pay attention to some of the following:

  1. In equation (11.6.1), the charge density is described as a volume charge density. You must change this equation to accommodate a line charge. Thus, the equation

    \begin{gather*} \EE(\rr) = \Int_{\textrm{space}} {1\over 4\pi\epsilon_0} {\rho(\rrp)\,(\rr-\rrp)\,d\tau'\over|\rr-\rrp|^3} \end{gather*}

    becomes

    \begin{gather*} \EE(\rr) = \Int_{\textrm{ring}} \frac{1}{4\pi\epsilon_0} \frac{\lambda(\rrp)\,(\rr-\rrp)\, d\vert\vec{r'}\vert}{|\rr-\rrp|^3} \end{gather*}
  2. Make sure to keep track of the difference between primed and unprimed variables, knowing which are changing at each step of the computation.

  3. You can only integrate vectors using rectangular basis vectors which are constant and therefore pull through the integral. It is fine and even preferable, however, to use curvilinear coordinates for the scalar parts of the integral.

  4. When expanding the integrand in the plane of the ring, the “small” quantity with respect to which you need to expand may consist of the sum of two terms, such as \(\epsilon=2\frac{R}{r}\cos\phi'+\frac{R^2}{r^2}\text{.}\) There is nothing wrong with this, but you may not have seen it before. When you truncate the series to a specific order, you will need to expand out powers of \(\epsilon\) and only keep the appropriate powers in the expansion.

You can check your work using this Mathematica notebook 1  which was used to construct Figure 11.7.1.

Figure 11.7.1. The electric field \(\EE\text{,}\) shown in a vertical plane with the \(z\)-axis at the left, superimposed on top of the level curves of \(V\text{.}\)
Answer.
\begin{align*} \amp \EE(s, \phi, z)\\ \amp= \frac{1}{4\pi\epsilon_0} \frac{Q}{2\pi R} \Int_0^{2\pi} \frac{\left( (s\cos\phi-R\cos\phi')\ii+(s\sin\phi-R\sin\phi')\jj+z\,\kk \right)\,R \,d\phi'} {\left({s^2+R^2-2sR\cos(\phi-\phi')+z^2}\right)^{3/2}} \end{align*}

Of course, you can combine the various constants in this expression. I chose not to so that you have a better chance of seeing where they came from.

math.oregonstate.edu/bridge/paradigms/vfering.nb